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  • Maharashtra Board Class 10 Science Part 1 Solutions | Physics & Chemistry

    Welcome to the complete guide for Maharashtra Board Class 10 Science Part 1 Solutions | Physics & Chemistry. This page provides chapter-wise textbook answers based on the latest Balbharati textbook and current MSBSHSE syllabus.

    All solutions are written in simple, step-by-step language to help students understand each concept clearly. Whether you are preparing for board exams or completing your homework, these solutions will guide you through every chapter.

    What You Will Find Here

    • Complete chapter-wise solved exercises from the Balbharati textbook
    • Step-by-step solutions with clear working for numerical problems
    • Theory answers written in student-friendly language
    • Important questions highlighted for board exam preparation
    • Regular updates as per the latest Maharashtra Board syllabus

    How to Use These Solutions

    1. Find the chapter you are studying from the list below
    2. Read the solution carefully and understand each step
    3. Try to solve similar problems on your own after reading
    4. Use the important questions section for exam revision

    Frequently Asked Questions

    Are these solutions free?

    Yes, all solutions on StateBoard Solutions are completely free. No registration or payment is needed.

    Are these solutions based on the latest syllabus?

    Yes. All content is based on the latest MSBSHSE syllabus and official Balbharati textbooks. We update our pages whenever the board revises the curriculum.

    Related Pages: Home | Class 10 Solutions | Class 12 Solutions | Question Papers

  • Maharashtra Board Class 10 Maths Solutions | Algebra & Geometry

    Finding clear, step-by-step Maharashtra Board Class 10 Maths solutions can make a huge difference in your board exam preparation. At StateBoard Solutions, we provide complete answers for both Algebra and Geometry textbooks, fully aligned with the latest MSBSHSE Class 10 syllabus.

    Our solutions are designed for SSC students who want to understand the working method behind each answer. Every practice set, problem set, and exercise question is solved with detailed steps and clear explanations.

    Table of Contents

    1. Class 10 Algebra Chapter-Wise Solutions
    2. Class 10 Geometry Chapter-Wise Solutions
    3. Important Formulas Quick Reference
    4. How to Score 90+ in SSC Maths Board Exam
    5. Frequently Asked Questions

    Class 10 Maths — Algebra Chapter-Wise Solutions

    The Algebra textbook for Maharashtra Board Class 10 has 6 chapters. Each chapter is linked below with complete practice set answers.

    ChapterTopicWhat You Will Learn
    Chapter 1Linear Equations in Two VariablesGraphical method, substitution, elimination, cross-multiplication
    Chapter 2Quadratic EquationsFactorisation, completing the square, quadratic formula, nature of roots
    Chapter 3Arithmetic ProgressionGeneral term, sum of n terms, word problems on AP
    Chapter 4Financial PlanningGST, income tax, share market basics, banking
    Chapter 5ProbabilityClassical probability, sample space, events, simple problems
    Chapter 6StatisticsMean, median, mode for grouped data, ogive, histogram

    Class 10 Maths — Geometry Chapter-Wise Solutions

    The Geometry textbook for Maharashtra Board Class 10 has 7 chapters. Solutions include diagram-based problems explained in detail.

    ChapterTopicKey Concepts
    Chapter 1SimilarityAA, SAS, SSS criteria, Basic Proportionality Theorem
    Chapter 2Pythagoras TheoremProof, converse, application in geometry problems
    Chapter 3CircleTangent, chord, angle subtended, cyclic quadrilateral
    Chapter 4Geometric ConstructionsDivision of line segment, tangent to circle, triangle constructions
    Chapter 5Coordinate GeometryDistance formula, section formula, area of triangle
    Chapter 6TrigonometryRatios, identities, heights and distances
    Chapter 7MensurationSurface area and volume of solids, combinations

    Important Formulas — Quick Reference

    Algebra Key Formulas

    • Quadratic Formula: x = [−b ± √(b²−4ac)] / 2a
    • AP General Term: tₙ = a + (n−1)d
    • Sum of AP: Sₙ = n/2 [2a + (n−1)d]
    • Probability: P(E) = Number of favourable outcomes / Total outcomes
    • Mean (Direct Method): x̄ = Σfₖxₖ / Σfₖ

    Geometry Key Formulas

    • Distance Formula: d = √[(x₂−x₁)² + (y₂−y₁)²]
    • Section Formula: (mx₂+nx₁)/(m+n), (my₂+ny₁)/(m+n)
    • Pythagoras: a² + b² = c²
    • Trigonometry: sinθ = Opposite/Hypotenuse, cosθ = Adjacent/Hypotenuse
    • Volume of Cylinder: πr²h  |  Cone: (1/3)πr²h  |  Sphere: (4/3)πr³

    How to Score 90+ in SSC Maths Board Exam

    1. Understand the paper pattern — The SSC Maths paper has MCQs, 2-mark, 3-mark, and 4-mark questions. Know the weightage of each chapter.
    2. Practice all practice sets — Every practice set in the textbook is important. Do not skip any.
    3. Learn formulas with derivations — Do not just memorize formulas. Understand where they come from so you can apply them in new problems.
    4. Attempt all geometry problems with proper diagrams — Diagrams carry marks in geometry. Always draw a neat, labelled figure.
    5. Revise previous year papers — Practice at least 5 years of past board papers to understand the pattern. Visit our SSC Question Papers section.
    6. Time management — In the exam, attempt the questions you are most confident about first. Allocate 2 minutes per mark as a general guideline.

    Frequently Asked Questions

    How many chapters are in Maharashtra Board Class 10 Maths?

    There are 13 chapters in total across two textbooks. Algebra has 6 chapters: Linear Equations, Quadratic Equations, Arithmetic Progression, Financial Planning, Probability, and Statistics. Geometry has 7 chapters: Similarity, Pythagoras Theorem, Circle, Constructions, Coordinate Geometry, Trigonometry, and Mensuration.

    What is the marking scheme for SSC Maths?

    Maharashtra SSC Maths is worth 80 marks (written exam) + 20 marks (internal assessment) = 100 marks total. The Algebra and Geometry papers are held separately, each worth 40 marks in the board exam. Students need to score at least 35% to pass each paper.

    Are Class 10 Maths solutions based on the Balbharati textbook?

    Yes. All Class 10 Maths solutions on StateBoard Solutions are based on the official Balbharati textbook published by the Maharashtra State Bureau of Textbook Production and Curriculum Research. The solutions follow the exact exercise order as in the textbook.

    Which chapters carry the most marks in SSC Maths board exam?

    In Algebra, Quadratic Equations, Arithmetic Progression, and Statistics typically carry more marks. In Geometry, Similarity, Trigonometry, and Mensuration are the highest-weightage chapters. Always check the latest official marking scheme from the MSBSHSE website for the current year.

    Related Solutions: Class 10 All Subjects | Class 10 Science Solutions | SSC Question Papers | Class 9 Solutions

  • Class 10 Maths Chapter 6 Statistics Solutions | Maharashtra Board SSC

    This page provides complete solutions for Maharashtra Board Class 10 Maths Chapter 6 — Statistics. Statistics in Class 10 covers measures of central tendency — Mean, Median, and Mode — for grouped data (data arranged in frequency tables). These three averages are essential for understanding data and are heavily tested in board exams.

    📋 Table of Contents

    Introduction to Statistics

    Statistics is the branch of mathematics dealing with collecting, organising, and interpreting data. In Class 10, we focus on three measures of central tendency for grouped data (data given in class intervals with frequencies).

    🔢 Statistics — All Key Formulas

    • Class Mark (midpoint): xᵢ = (upper limit + lower limit) / 2
    • MEAN (Direct Method): x̄ = Σ(fᵢxᵢ) / Σfᵢ
    • MEAN (Assumed Mean): x̄ = A + Σ(fᵢdᵢ)/Σfᵢ where dᵢ = xᵢ − A
    • MEAN (Step Deviation): x̄ = A + (Σfᵢuᵢ/Σfᵢ) × h where uᵢ = (xᵢ−A)/h
    • MEDIAN: M = L + [(n/2 − cf) / f] × h
    • MODE: Mo = L + [(f₁−f₀) / (2f₁−f₀−f₂)] × h
    • Empirical Relation: Mode = 3 Median − 2 Mean

    Mean of Grouped Data

    The mean (arithmetic average) for grouped data is calculated by multiplying each class mark by its frequency, adding all products, then dividing by total frequency.

    Practice Set 6.1 — Mean Solutions

    Q: Find the mean of the following data: Class: 0-10, 10-20, 20-30, 30-40, 40-50. Frequency: 5, 10, 25, 30, 10

    Step 1: Find class marks (midpoints): x₁=5, x₂=15, x₃=25, x₄=35, x₅=45

    Step 2: Calculate fᵢxᵢ: 5×5=25, 10×15=150, 25×25=625, 30×35=1050, 10×45=450

    Step 3: Σfᵢxᵢ = 25+150+625+1050+450 = 2300

    Step 4: Σfᵢ = 5+10+25+30+10 = 80

    Step 5: Mean = Σfᵢxᵢ / Σfᵢ = 2300/80 = 28.75

    ✅ Answer: Mean = 28.75

    Q: Find mean using Step Deviation method: Class: 10-20, 20-30, 30-40, 40-50, 50-60. Frequency: 4, 8, 14, 10, 4

    Step 1: Class marks: 15, 25, 35, 45, 55. Assume A = 35, h = 10

    Step 2: uᵢ = (xᵢ − 35)/10: −2, −1, 0, 1, 2

    Step 3: fᵢuᵢ: 4×(−2)=−8, 8×(−1)=−8, 14×0=0, 10×1=10, 4×2=8

    Step 4: Σfᵢuᵢ = −8−8+0+10+8 = 2

    Step 5: Σfᵢ = 4+8+14+10+4 = 40

    Step 6: Mean = A + (Σfᵢuᵢ/Σfᵢ)×h = 35 + (2/40)×10 = 35 + 0.5 = 35.5

    ✅ Answer: Mean = 35.5

    Median of Grouped Data

    The median is the middle value. For grouped data, first find the median class (where cumulative frequency ≥ n/2), then apply the formula: M = L + [(n/2 − cf) / f] × h

    Practice Set 6.2 — Median Solutions

    Q: Find the median: Marks: 0-10, 10-20, 20-30, 30-40, 40-50. Frequency: 3, 5, 7, 4, 1. Total n = 20

    Step 1: Cumulative frequencies: 3, 8, 15, 19, 20

    Step 2: n = 20, n/2 = 10

    Step 3: Median class: cf just below 10 is 8 (0-10 class), so median class is 20-30 (where cf becomes 15 ≥ 10)

    Step 4: L = 20, cf = 8 (cumulative before 20-30), f = 7, h = 10

    Step 5: Median = 20 + [(10 − 8) / 7] × 10 = 20 + (2/7)×10 = 20 + 2.86 = 22.86

    ✅ Answer: Median ≈ 22.86

    Q: Find the median: Class: 100-120, 120-140, 140-160, 160-180, 180-200. Frequency: 12, 14, 8, 6, 10. n = 50

    Step 1: Cumulative frequencies: 12, 26, 34, 40, 50

    Step 2: n/2 = 25

    Step 3: Cumulative frequency first exceeds 25 at 26 (class 120-140). Median class = 120-140

    Step 4: L = 120, cf = 12, f = 14, h = 20

    Step 5: Median = 120 + [(25−12)/14] × 20 = 120 + (13/14)×20 = 120 + 18.57 = 138.57

    ✅ Answer: Median ≈ 138.57

    Mode of Grouped Data

    The mode is the most frequently occurring value. For grouped data, the modal class is the class with the highest frequency. The mode formula gives the exact value within the modal class.

    Practice Set 6.3 — Mode Solutions

    Q: Find the mode: Age: 0-10, 10-20, 20-30, 30-40, 40-50. Frequency: 5, 8, 15, 10, 2

    Step 1: Modal class = 20-30 (highest frequency = 15)

    Step 2: L = 20, f₁ = 15, f₀ = 8 (frequency before), f₂ = 10 (frequency after), h = 10

    Step 3: Mode = L + [(f₁−f₀)/(2f₁−f₀−f₂)] × h

    Step 4: = 20 + [(15−8)/(30−8−10)] × 10

    Step 5: = 20 + [7/12] × 10

    Step 6: = 20 + 5.83 = 25.83

    ✅ Answer: Mode ≈ 25.83

    Q: Find mode: Wages (₹): 120-140, 140-160, 160-180, 180-200, 200-220. Workers: 6, 9, 17, 12, 4

    Step 1: Modal class = 160-180 (highest frequency = 17)

    Step 2: L = 160, f₁ = 17, f₀ = 9, f₂ = 12, h = 20

    Step 3: Mode = 160 + [(17−9)/(34−9−12)] × 20

    Step 4: = 160 + [8/13] × 20

    Step 5: = 160 + 12.31 = 172.31

    ✅ Answer: Mode ≈ ₹172.31

    Practice Set 6.4 — Cumulative Frequency and Ogive

    A cumulative frequency table shows the running total of frequencies. An ogive (cumulative frequency curve) is the graph of cumulative frequencies against upper class boundaries. It is used to find the median graphically.

    Q: Draw a less-than ogive for: Class: 0-5, 5-10, 10-15, 15-20, 20-25. Frequency: 3, 7, 10, 8, 2

    Step 1: Less-than cumulative frequencies: below 5: 3, below 10: 10, below 15: 20, below 20: 28, below 25: 30

    Step 2: Plot points: (5,3), (10,10), (15,20), (20,28), (25,30)

    Step 3: Join the points with a smooth curve — this is the less-than ogive.

    Step 4: To find median from ogive: Draw horizontal line at n/2 = 15, note the x-value — this is the median.

    Step 5: From the ogive, median ≈ 13 (where cumulative frequency = 15)

    ✅ Answer: Ogive plotted; Median ≈ 13 (read from graph)

    Relation Between Mean, Median and Mode

    🔢 Empirical Relationship

    • Mode = 3 Median − 2 Mean
    • This relation holds approximately for moderately skewed distributions
    • If Mean = Median = Mode → data is symmetrically distributed
    • Use this formula to find one average when other two are known

    Q: If Mean = 26 and Median = 23, find Mode using empirical relation.

    Step 1: Mode = 3 Median − 2 Mean

    Step 2: Mode = 3(23) − 2(26) = 69 − 52 = 17

    ✅ Answer: Mode = 17

    Frequently Asked Questions

    What is the difference between Mean, Median and Mode?

    Mean is the arithmetic average of all values. Median is the middle value when data is arranged in order. Mode is the most frequently occurring value. All three are measures of central tendency but describe different aspects of the data.

    When should I use Assumed Mean method instead of Direct Method?

    Use the Assumed Mean (or Step Deviation) method when the class marks are large numbers. It reduces computation by working with smaller numbers (deviations from an assumed mean). Both methods give the same answer.

    How many marks does Chapter 6 Statistics carry in SSC board exam?

    Statistics carries 8 to 10 marks in the SSC Algebra paper — making it one of the highest-weightage chapters. Typically there is one full problem (5-6 marks) requiring a frequency table with all calculations for Mean, Median, and/or Mode.

    What is an ogive and how is it used in exams?

    An ogive is a cumulative frequency curve (S-shaped). To draw it: plot cumulative frequency vs upper class boundary, then join with smooth curve. In exams, you may be asked to find the median from the ogive, or draw both less-than and more-than ogives and find their intersection (which gives the median).

    🔗 Related: ← Chapter 5: Probability | Class 10 Geometry Chapters → | Class 10 All Subjects | SSC Question Papers

  • Class 10 Maths Chapter 5 Probability Solutions | Maharashtra Board SSC

    This page provides complete solutions for Maharashtra Board Class 10 Maths Chapter 5 — Probability. Probability deals with the likelihood of events occurring. This chapter introduces classical probability, sample space, and solving problems involving coins, dice, cards, and coloured balls.

    📋 Table of Contents

    Introduction to Probability

    Probability is the measure of the likelihood of an event occurring. It was formally developed by mathematicians Blaise Pascal and Pierre de Fermat. Probability helps us make predictions when outcomes are uncertain.

    🔢 Probability Formulas

    • P(Event E) = n(E) / n(S) where n(E) = favourable outcomes, n(S) = total outcomes
    • 0 ≤ P(E) ≤ 1 (probability always between 0 and 1)
    • P(E) = 0 → impossible event
    • P(E) = 1 → certain/sure event
    • P(E) + P(E') = 1 → P(E') = 1 − P(E) (complementary event)
    • Sample Space (S) = set of all possible outcomes
    • Event (E) = subset of sample space
    • Equally likely outcomes → each outcome has equal chance

    Key Concepts and Terminology

    • Experiment: Any activity with uncertain outcomes (e.g., tossing a coin)
    • Sample Space (S): Complete list of all possible outcomes
    • Event (E): A specific outcome or set of outcomes we are interested in
    • Favourable outcomes: Outcomes that satisfy the condition of the event
    • Equally likely outcomes: Each outcome has the same probability

    Standard Sample Spaces:

    • One coin: S = {H, T} → n(S) = 2
    • Two coins: S = {HH, HT, TH, TT} → n(S) = 4
    • Three coins: n(S) = 8
    • One die: S = {1,2,3,4,5,6} → n(S) = 6
    • Two dice: n(S) = 36
    • Pack of cards: n(S) = 52 (4 suits × 13 cards each)

    Practice Set 5.1 — Basic Probability

    Q: A bag contains 3 red and 5 blue balls. A ball is drawn at random. Find the probability of drawing (i) a red ball (ii) a blue ball.

    Step 1: Total balls = 3 + 5 = 8. So n(S) = 8.

    Step 2: (i) Favourable outcomes for red = 3. P(red) = 3/8

    Step 3: (ii) Favourable outcomes for blue = 5. P(blue) = 5/8

    Step 4: Check: P(red) + P(blue) = 3/8 + 5/8 = 8/8 = 1 ✓

    ✅ Answer: P(red) = 3/8, P(blue) = 5/8

    Q: A box contains 5 red, 4 green, and 3 yellow marbles. One marble is picked randomly. Find probability of (i) red (ii) green (iii) yellow.

    Step 1: Total = 5 + 4 + 3 = 12 marbles

    Step 2: (i) P(red) = 5/12

    Step 3: (ii) P(green) = 4/12 = 1/3

    Step 4: (iii) P(yellow) = 3/12 = 1/4

    Step 5: Sum = 5/12 + 4/12 + 3/12 = 12/12 = 1 ✓

    ✅ Answer: P(red)=5/12, P(green)=1/3, P(yellow)=1/4

    Practice Set 5.2 — Coins and Dice

    Q: Two coins are tossed simultaneously. Find probability of (i) exactly one head (ii) both heads (iii) no head

    Step 1: Sample Space S = {{HH, HT, TH, TT}}. n(S) = 4

    Step 2: (i) Exactly one head: {{HT, TH}} → P = 2/4 = 1/2

    Step 3: (ii) Both heads: {{HH}} → P = 1/4

    Step 4: (iii) No head (both tails): {{TT}} → P = 1/4

    Step 5: Check: 1/2 + 1/4 + 1/4 = 1 ✓

    ✅ Answer: P(exactly one head) = 1/2, P(both heads) = 1/4, P(no head) = 1/4

    Q: A die is thrown. Find probability of getting (i) a prime number (ii) a number divisible by 3 (iii) a number greater than 4

    Step 1: Sample Space = {{1,2,3,4,5,6}}. n(S) = 6

    Step 2: (i) Prime numbers: {{2,3,5}} → P = 3/6 = 1/2

    Step 3: (ii) Divisible by 3: {{3,6}} → P = 2/6 = 1/3

    Step 4: (iii) Greater than 4: {{5,6}} → P = 2/6 = 1/3

    ✅ Answer: P(prime) = 1/2, P(div by 3) = 1/3, P(>4) = 1/3

    Q: Two dice are thrown simultaneously. Find P(sum = 7)

    Step 1: Total outcomes n(S) = 6×6 = 36

    Step 2: Favourable outcomes (sum=7): (1,6),(2,5),(3,4),(4,3),(5,2),(6,1) → 6 outcomes

    Step 3: P(sum = 7) = 6/36 = 1/6

    ✅ Answer: P(sum = 7) = 1/6

    Q: Two dice are thrown. Find P(sum > 10)

    Step 1: n(S) = 36

    Step 2: Sum > 10 means sum = 11 or 12.

    Step 3: Sum = 11: (5,6),(6,5) → 2 outcomes

    Step 4: Sum = 12: (6,6) → 1 outcome

    Step 5: Total favourable = 3

    Step 6: P(sum > 10) = 3/36 = 1/12

    ✅ Answer: P(sum > 10) = 1/12

    Practice Set 5.3 — Playing Cards

    A standard deck has 52 cards = 4 suits (Hearts ♥, Diamonds ♦, Clubs ♣, Spades ♠) × 13 cards each (A, 2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K). Red cards = Hearts + Diamonds = 26. Black cards = Clubs + Spades = 26. Face cards = J, Q, K = 12 total.

    Q: A card is drawn from a well-shuffled pack of 52 cards. Find P(i) a king (ii) a red card (iii) a face card (iv) a diamond

    Step 1: n(S) = 52

    Step 2: (i) Kings: 4 (one per suit) → P = 4/52 = 1/13

    Step 3: (ii) Red cards: 26 → P = 26/52 = 1/2

    Step 4: (iii) Face cards (J,Q,K): 3×4 = 12 → P = 12/52 = 3/13

    Step 5: (iv) Diamonds: 13 → P = 13/52 = 1/4

    ✅ Answer: P(king)=1/13, P(red)=1/2, P(face)=3/13, P(diamond)=1/4

    Q: Find P(a card drawn is an ace or a king)

    Step 1: n(S) = 52

    Step 2: Aces = 4, Kings = 4

    Step 3: Ace OR King = 4 + 4 = 8 cards

    Step 4: P = 8/52 = 2/13

    ✅ Answer: P(ace or king) = 2/13

    Practice Set 5.4 — Mixed Problems

    Q: A number is chosen at random from 1 to 25. Find P(prime number)

    Step 1: n(S) = 25

    Step 2: Prime numbers from 1 to 25: 2,3,5,7,11,13,17,19,23 → 9 primes

    Step 3: P(prime) = 9/25

    ✅ Answer: P(prime) = 9/25

    Q: In a class of 40 students, 15 like Maths, 20 like Science, and 5 like both. A student is selected at random. Find P(likes Maths or Science).

    Step 1: n(S) = 40

    Step 2: Likes Maths or Science = 15 + 20 − 5 = 30 (using addition principle)

    Step 3: P(Maths or Science) = 30/40 = 3/4

    ✅ Answer: P(Maths or Science) = 3/4

    Complementary Events

    The complementary event E’ (read as ‘E prime’ or ‘not E’) consists of all outcomes NOT in E. The fundamental rule is: P(E) + P(E’) = 1.

    Q: The probability that it will rain tomorrow is 0.65. Find P(it will NOT rain).

    Step 1: P(rain) = 0.65

    Step 2: P(not rain) = 1 − P(rain) = 1 − 0.65 = 0.35

    ✅ Answer: P(no rain) = 0.35

    Q: A bag has 8 balls: 3 red, 5 blue. P(not red) = ?

    Step 1: P(red) = 3/8

    Step 2: P(not red) = 1 − 3/8 = 5/8

    Step 3: Alternatively: P(blue) = 5/8 = P(not red) ✓

    ✅ Answer: P(not red) = 5/8

    Frequently Asked Questions

    What is the probability of getting a head when a coin is tossed?

    P(head) = 1/2. A fair coin has two equally likely outcomes — head and tail. Since only one of them is a head, probability = 1/2 or 0.5.

    Can probability be greater than 1?

    No. Probability is always between 0 and 1 (inclusive). P = 0 means impossible, P = 1 means certain. If your calculated probability is greater than 1, you have made an error.

    How many marks does Chapter 5 carry in SSC board exam?

    Probability carries 5 to 7 marks in the SSC Algebra paper. Typically there is one short problem (2 marks) and one long problem (3-4 marks). Problems on coins, dice, balls in bags, and playing cards are most common.

    What is the difference between ‘or’ and ‘and’ in probability?

    ‘Or’ means at least one of the events happens (union). ‘And’ means both events happen simultaneously (intersection). For Class 10, focus on ‘or’ using the addition rule: P(A or B) = P(A) + P(B) − P(A and B).

    🔗 Related: ← Chapter 4: Financial Planning | Chapter 6: Statistics → | Class 10 Maths All Chapters

  • Maharashtra Board Class 12 Physics Solutions | HSC All Chapters

    Maharashtra Board Class 12 Physics is one of the most important and scoring subjects for HSC Science students. A solid understanding of concepts combined with regular practice of numerical problems is the key to achieving high marks. At StateBoard Solutions, we provide complete chapter-wise Physics solutions for all chapters of the Maharashtra State Board Class 12 (HSC) textbook.

    Table of Contents

    1. Chapter-Wise Solutions List
    2. High-Weightage Topics for HSC Physics
    3. How to Solve HSC Physics Numericals
    4. Frequently Asked Questions

    Chapter-Wise Physics Solutions — Class 12 HSC

    All 16 chapters of the Maharashtra Board Class 12 Physics textbook are covered below. Click any chapter link to view complete solutions including theory answers, derivations, and numerical problem solutions.

    Chapter No.Chapter NameKey Topics
    1Circular MotionAngular velocity, centripetal force, banking of roads, conical pendulum
    2GravitationKepler’s laws, escape velocity, orbital motion, gravitational potential
    3Rotational MotionMoment of inertia, torque, angular momentum, rolling motion
    4OscillationsSHM, period, amplitude, energy in SHM, damped oscillations
    5ElasticityStress, strain, Young’s modulus, Hooke’s law, elastic energy
    6Surface TensionSurface tension, capillary rise, excess pressure in drops and bubbles
    7Wave MotionProgressive waves, wave equation, speed of sound, Doppler effect
    8Stationary WavesNodes, antinodes, modes of vibration, resonance
    9Kinetic Theory of Gases & RadiationKinetic energy, ideal gas laws, blackbody radiation, Wien’s law
    10Wave OpticsInterference, Young’s double slit, diffraction, polarisation
    11ElectrostaticsCoulomb’s law, electric field, potential, capacitors
    12Current ElectricityOhm’s law, Kirchhoff’s laws, Wheatstone bridge, potentiometer
    13Magnetic Effects of Electric CurrentBiot-Savart law, Ampere’s law, solenoid, magnetic force
    14MagnetismBar magnet, Earth’s magnetism, diamagnetic, paramagnetic, ferromagnetic
    15Electromagnetic InductionFaraday’s law, Lenz’s law, self-induction, mutual induction, AC generator
    16Electrons, Photons & SemiconductorsPhotoelectric effect, de Broglie wavelength, p-n junction, logic gates

    High-Weightage Topics for HSC Physics Board Exam

    Based on analysis of past HSC Physics question papers, these chapters carry the most marks and should be given priority during preparation:

    • ⭐ Circular Motion — Numericals on centripetal acceleration and banking are very common
    • ⭐ Rotational Motion — Moment of inertia derivations and rolling motion
    • ⭐ Electrostatics — Derivation of electric field and potential are frequently asked
    • ⭐ Wave Optics — Young’s double slit experiment theory and numericals
    • ⭐ Current Electricity — Kirchhoff’s laws and circuit problems
    • ⭐ Electromagnetic Induction — Faraday’s law derivations and self-inductance
    • ⭐ Semiconductors — Photoelectric effect, logic gates, transistor circuits

    How to Solve HSC Physics Numericals Effectively

    1. Write Given Data First — Always list all given values with units before starting the solution. This also earns you partial marks.
    2. Identify the Correct Formula — Write the formula you are using clearly, then substitute values.
    3. Check Units at Every Step — Physics numericals often go wrong due to unit conversion errors. Always convert to SI units before substituting.
    4. Show All Intermediate Steps — In board exams, step marking is applied. Even if your final answer is wrong, correct intermediate steps earn marks.
    5. Box Your Final Answer — Clearly mark the final answer with its unit. An answer without units is considered incomplete.

    Frequently Asked Questions

    How many chapters are in Maharashtra Board Class 12 Physics?

    The Maharashtra Board Class 12 Physics textbook has 16 chapters covering topics from Circular Motion and Gravitation to Semiconductors and Electromagnetic Induction. All chapters are important for the HSC board exam.

    What percentage of HSC Physics paper is numericals?

    Approximately 40–50% of the HSC Physics paper consists of numerical problems and derivations. Theory questions, definitions, and short notes cover the remaining marks. Students should practice at least 2–3 numericals from every chapter.

    Are derivations important for HSC Physics?

    Yes, derivations carry significant marks in HSC Physics. Important derivations include the equation of motion for SHM, expression for moment of inertia, Faraday’s law derivation, and the Young’s double slit formula. Practice writing these with all steps clearly.

    Where can I find HSC Physics previous year question papers?

    You can find Maharashtra Board HSC Physics previous year question papers in our dedicated Class 12 Question Papers section. Practicing past papers is one of the most effective ways to prepare for board exams.

    Related Solutions: Class 12 All Subjects | Class 12 Chemistry | Class 12 Maths | HSC Important Questions